The correct geometries for the metal carbonyl clusters, A‐C

A. [Ru6(CO)17B]-

B. [Os6(CO)18P]-

C. [Os4(CO)16]

are

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CSIR-UGC (NET) Chemical Science: Held on (16 Feb 2022)
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  1. A: pentagonal bipyramidal, B: trigonal prismatic, and C: tetrahedral
  2. A: pentagonal bipyramidal, B: octahedral, and C: square
  3. A: octahedral, B: trigonal prismatic, and C: tetrahedral
  4. A: octahedral, B: trigonal prismatic, and C: square

Answer (Detailed Solution Below)

Option 4 : A: octahedral, B: trigonal prismatic, and C: square
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Detailed Solution

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Concept - 

  • The gemoteries of the organometaalics compound depends on the bonding molecular orbital and bonding molecular orbital can be calculated by calculating cluster electrons 
  • Cluster electrons can be calculated as - Valence electron of metal * No. of metal present + Electron donated by ligand * No. of ligands + Electron onated by any atom present 

Explanation - 
For  [Ru6(CO)17B]- = 8*6+2*17+3+1 = 83 

Hence, bonding molecular orbital = 43

Geometery = Octahedral (According to the standard geometery chard given)

 [Os6(CO)18P]   = 8*6+2*18+5+1 = 90

Hence, Bonding molecular orbital = 45

Geometery = Trigonal BiPrismatic

[Os4(CO)16] = 8*4+2*16 = 64

Bomding molecular orbital = 32

So, Geometry = Square Plannar

Conclusion:-

So, The correct geometries A: octahedral, B: trigonal prismatic, and C: square

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