ప్రారంభ విలువ సమస్యను పరిష్కరించండి, dy = ex + 2y dx , y (0) = 0.

  1. y = 
  2. y = 
  3. y = 
  4. y = 3 - 2e

Answer (Detailed Solution Below)

Option 3 : y = 
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Detailed Solution

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భావన:

ln ey = y .

లెక్కింపు:

మనకు ఉంది,

dy =  ex + 2y dx 

⇒ dy = ex . e2y dx 

⇒ e-2y dy = ex dx 

రెండు వైపులా సమగ్రపరచడం ద్వారా, మేము పొందుతాము

 

 ​

​e-2y  = ex + C          .... (i) 

y (0) = 0 , అంటే x = 0 వద్ద , y = 0 , దీనిని (i) లో ఉంచడం,

 = 1 + సC

⇒ సి = .

C = (i) లో పెట్టడం, మనకు లభిస్తుంది

C =  in (i) , we get 

 e-2y = ex  

⇒ e-2y = - 2ex  + 3

⇒ e2y =  

⇒ 2y = ln  

⇒ y = . 

 

సరైన ఎంపిక 3.

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