Question
Download Solution PDFPQ is the diameter of a circle with centre ‘O’. draw tangent at P, mark a point R on the circle and produce QR to meet the tangent at P at S. If ∠ PSQ = 48° then ∠ PQR =
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
PQ is the diameter of a circle with center 'O'. Tangent drawn at P meets QR (produced) at S. ∠PSQ = 48º.
Formula Used:
Angle in the semicircle = 90º
Calculation:
In triangle PQR:
Since PQ is diameter ⇒ ∠PRQ = 90°
In triangle PSQ:
∠PSQ is the exterior angle to triangle PQR
∠PSQ = 48º
∠SPQ = 90° (angle made by tangent and chord)
∠PQS = 90 - 48 = 42°
∠PQS = ∠PQR = 42°
∴ The value of ∠PQR is 42°.
Last updated on Feb 11, 2025
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