Question
Download Solution PDFIf the distance travelled by a car in ‘t’ seconds is given by d = 4t2– 3. If the car started at 9 am, what is the distance travelled by the car between 9.02 am and 9.03 am ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Distance travelled by the car is given by: d = 4t2 – 3
The car started at 9:00 am.
We need to find the distance travelled between 9:02 am (t = 120 seconds) and 9:03 am (t = 180 seconds).
Formula Used:
Distance travelled in a time interval = d(t2) – d(t1)
Calculation:
At t = 120 seconds:
d(120) = 4 × (120)2 – 3
d(120) = 4 × 14400 – 3
d(120) = 57600 – 3
d(120) = 57597
At t = 180 seconds:
d(180) = 4 × (180)2 – 3
d(180) = 4 × 32400 – 3
d(180) = 129600 – 3
d(180) = 129597
Distance travelled between 9:02 am and 9:03 am:
Distance = d(180) – d(120)
⇒ Distance = 129597 – 57597
⇒ Distance = 72000
The distance travelled by the car between 9:02 am and 9:03 am is 72000 units.
Last updated on Feb 11, 2025
Kerala Public Service Commission (KPSC) will release a new notification for the Kerala PSC Degree Level Exam. The exam will be conducted to recruit candidates for the post of Sales Assistant, Armed Police SI, Excise Inspector, etc. Candidates with a Graduation degree will only be selected under the recruitment process. Candidates can refer to the Kerala PSC Degree Level Exam Preparation Tips to boost their preparation and score well in the exam.
-> A bachelor's degree in any field from a recognized university and the ability to converse in Malayalam.
-> The recruitment process is done in several stages, which include a Preliminary Exam, Main Exam, and Interview.
-> Candidates who successfully complete the selection process will be considered for various positions within Kerala State Government departments.