Question
Download Solution PDFसाजिदने 60 किमी/तास वेगाने 6 तास आणि 50 किमी/तास वेगाने 4 तास गाडी चालवली. संपूर्ण प्रवासात त्याचा सरासरी वेग किती होता?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेली माहिती:
साजिद 60 किमी/तास वेगाने 6 तास वेगाने गाडी चालवतो
साजिद 50 किमी/तास वेगाने 4 तास गाडी चालवतो
संकल्पना: सरासरी वेग = एकूण अंतर / एकूण वेळ
उपाय:
⇒ एकूण कापलेले अंतर = (6 तास × 60 किमी/तास) + (4 तास × 50 किमी/तास) = 360 किमी + 200 किमी = 560 किमी
⇒ एकूण वेळ = 6 तास + 4 तास = 10 तास
⇒ सरासरी वेग = 560 किमी / 10 तास = 56 किमी / तास
म्हणून, संपूर्ण प्रवासासाठी साजिदचा सरासरी वेग 56 किमी/तास आहे.
Last updated on Jun 27, 2025
-> SSC MTS 2025 Notification has been released by the Staff Selection Commission (SSC) on the official website on 26th June, 2025.
-> A total of 1075 Vacancies have been announced for the post of Havaldar in CBIC and CBN.
-> The last date to apply online will be 24th July 2025 as per the SSC Exam Calendar 2025-26.
-> The selection of the candidates for the post of SSC MTS is based on Computer Based Examination.
-> Candidates with basic eligibility criteria of the 10th class were eligible to appear for the examination.
-> Candidates must attempt the SSC MTS Mock tests and SSC MTS Previous year papers for preparation.