ΔABC च्या वर्तुळकेंद्र I पासून, BC वर लंब ID काढला आहे. जर ∠BAC = 60 असेल तर ∠BID चे मूल्य आहे

  1. 75°
  2. 60°
  3. 45°
  4. 80°

Answer (Detailed Solution Below)

Option 2 : 60°
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ST 1: B.Ed. Common Entrance (Teaching Aptitude)
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दिलेल्याप्रमाणे:

∠BAC = 60°

वापरलेली संकल्पना:

एका वर्तुळाच्या मध्यभागी असलेल्या लंबाद्वारे जोडलेला कोन वर्तुळाच्या उर्वरित भागावरील कोणत्याही बिंदूने जोडलेला कोन दुप्पट असतो.

गणना:

F1 Vikash Kumar 7.7.21 Pallavi D2

∠BIC = 2 × ∠BAC = 2 × 60° = 120° 

∴ ∠BID = ∠DIC = 120°/2 = 60° 
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