Question
Download Solution PDFIn 60‐degrees PWM inverter power supply,
A. Power devices are made 'ON' for 1/3 of the cycle.
B. Power devices are made 'OFF' for 1/3 of the cycle.
C. The phase voltage = 0.57735 Vsupply.
D. Line voltage = Vsupply.
E. Line voltage < Vsupply.
Choose the correct answer from the options given below:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPulse width modulation
In the given figure, 2d represents the total pulse width or the time duration for which the device is conducted in the one-half cycle (80°)
In 60-degree PWM, the device conducts for 120°.
So, the device is made 'ON' for 2/3 of the cycle. Hence, statement A is incorrect.
and the device is made 'OFF' for 1/3 of the cycle. Hence, statement B is correct.
The phase voltage is given by:
\(V_p=\sqrt{120\over 360}\space V_{supply}\)
The phase voltage = 0.57735 Vsupply
Hence, statement C is correct.
The line voltage in PWM is always less than the supply voltage.
Hence, statement E is correct.
The correct answer is option A.
Last updated on Jun 6, 2025
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