Question
Download Solution PDFIf G is gauge in metres, V is speed of trains in km/hour and R is radius of a curve in metres, the equilibrium super elevation is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Equilibrium cant \(= \frac{{{\rm{G}}{{\rm{V}}^2}}}{{127{\rm{R}}}}\)
V - Design speed (kmph)
R - Radius of curvature (m)
For B.G track G = 1.676
\(\begin{array}{l} {\rm{Cant}} = \frac{{1.676{\rm{\;}}{{\rm{V}}^2}}}{{127{\rm{\;R}}}}{\rm{m}}\\ {\rm{e}} = \frac{{1.315{\rm{\;}}{{\rm{V}}^2}}}{{\rm{R}}}{\rm{cm}} \end{array}\)
Last updated on Jun 4, 2025
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