Question
Download Solution PDFIf a + b + c = 6 and a2 + b2 + c2 = 14, then what is the value of (a - b)2 + (b - c)2 + (c - a)2 ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
a + b + c = 6 and a2 + b2 + c2 = 14,
Calculation:
Let putting a = 1 , b = 2 and c = 3
a + b + c = 1 + 2 + 3 = 6
So the value of
(a - b)2 + (b - c)2 + (c - a)2 .
⇒ (1 - 2)2 + (2 - 3)2 + (3- 1)2 .
⇒ 1 + 1 + 4 = 6
∴ The correct option is 4
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