Question
Download Solution PDFHow much water must be added to 200 litres of 60% solution of acid to reduce it to a 30% solution of acid? (In litres)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Quantity of acid solution = 200 liters
Calculation:
Acid in 200 litres = 60% of 200
= 60/100 × 200
= 120 liters
Suppose p liters of water are added.
Then, there are 120 liters of acid in (200+ p) liters of acidic solution.
According to the questions
30% of (200+ p) = 120
⇒ 30/100 × (200+p) = 120
⇒ 3× (200+p) = 120× 10
⇒ 600 + 3p = 1200
⇒3p = 600
⇒ p = 600/3
⇒ p = 200
∴ The correct answer is 200 liters.
Alternate Method:
Formula used:
In 'A ' liters of x% acidic liquid, the amount of water to be added to make y% acidic liquid is A(x-y) /y liters.
calculation:
Applying the above formula
The quantity of water to be added = 200× (60-30) / 30
= 200 liters
∴ The correct answer is 200 liters.
Last updated on Jun 12, 2025
-> OSSC CGL Final Merit List has been released on the official website.
->The merit list consist the names of the candidates found suitable after the CV round.
->Earlier,The OSSC CGL Call Letter had been released for the Document Verification (Advt No.1249/OSSC).
-> Interested candidates registered from 29th November 2024 to 28th December 2024.
-> The recruitment is also ongoing for 543 vacancies (Advt. No. 129/OSSC). The Prelims was held on 20th October 2024 and thee Mains Exam will be scheduled in February/ March 2025.
-> The selection process includes Prelims, Mains, Skill Test, and Document Verification.
-> To score well in the exam, you may enhance your preparation by solving the OSSC CGL Previous Years' Papers.
-> Candidates can also attend the OSSC CGL Test Series which helps to find the difficulty level.