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मान लीजिए कि X का अंतराल [0, 100][ पर एकसमान वितरण है। मान लीजिए Y, X से छोटा या उसके बराबर सबसे बड़ा पूर्णांक दर्शाता है। निम्न में से कौन सा सत्य है?

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CSIR-UGC (NET) Mathematical Science: Held on (26 Nov 2020)
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  1. P(Y ≤ 25) = 1/4
  2. P(Y ≤ 25) = 26/100
  3. E(Y) = 50
  4. E(Y) = 101/2

Answer (Detailed Solution Below)

Option 2 : P(Y ≤ 25) = 26/100
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P(Y ≤ 25) = 26/100

विकल्प (2) सही है

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-> The CSIR NET June 2025 Exam Schedule has been released on its official website.The exam will be held on 28th July 2025.

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