Question
Download Solution PDFΔABC में D, BC पर एक बिंदु है। AB को E तक बढ़ाया जाता है और AC को F तक बढ़ाया जाता है। एक वृत्त DEF से होकर गुजरता है जहाँ AB = 10 सेमी, AC = 8.6 सेमी और BC = 6.4, तो BE = ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
समान बाह्य बिंदु से एक वृत्त के लिए स्पर्शरेखा खंड बराबर होते हैं।
गणना:
दिया है, AB = 10 सेमी, AC = 8.6 सेमी और BC = 6.4 सेमी
माना BE = x सेमी और CF = y सेमी
जैसा कि हम जानते हैं,
BE = BD [स्पर्शरेखाएँ]
DC = CF [स्पर्शरेखाएँ]
AE = AF [स्पर्शरेखाएँ]
AB + BE = AC + CF
⇒ 10 + x = 8.6 + y
⇒ x – y = 8.6 – 10
⇒ x – y = - 1.4 ----(1)
BD + DC = 6.4
⇒ x + y = 6.4 ----(2)
समीकरण (1) और समीकरण (2) से
⇒ x = 2.5
∴ BE = 2.5 cm
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