Question
Download Solution PDFयदि \(\cos x = \frac{5}{{13}}\), x चौथे चतुर्थांश में है, और अन्य पांच त्रिकोणमितीय फलनों का मान निर्धारित करें?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
cos(x) = 5/13
संकल्पना:
चौथे चतुर्थांश में केवल cos(x) और sec(x) धनात्मक हैं।
x चौथे चतुर्थांश में है तो cos(x) धनात्मक होगा और sin (x) ऋणात्मक होगा इसलिए tan (x) ऋणात्मक होगा।
स्पष्टीकरण:
cos(x) = आधार/कर्ण
⇒ आधार = 5, कर्ण = 13
∵ B2 + P2 = H2
⇒ 52 + P2 = 132
∴ P = √(132 - 52)
= 12
∴ अन्य t-फ़लन:
sin(x) = -12/13
cosec(x) = -13/12
tan(x) = -12/5
cot(x) = -5/12
sec(x) = 13/5
Last updated on May 26, 2025
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