यदि μ4, = 199, μ3 = 50 और μ2 = 8, तो अतिरिक्त कुकुदता का मान है:

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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )
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  1. 1.109
  2. 0.109
  3. 3.109
  4. 2.109

Answer (Detailed Solution Below)

Option 2 : 0.109
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SSC CGL Tier 1 2025 Full Test - 01
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दिया है

μ4 = 199

μ3 = 50

μ2 = 8

सूत्र

कुकुदता a4= μ4/(μ2)2

अतिरिक्त कुकुदता = a4 – 3

गणना

a4 = 199/(8)2

⇒ 199/64

⇒ 3.109

⇒ अतिरिक्त कुकुदता को gद्वारा दर्शाया जाता है

⇒ g2 = a4 – 3

⇒ 3.109 – 3

∴ अतिरिक्त कुकुदता 0.109 है।

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