दिए गए परिपथ में नोड 'a' पर वोल्टेज ज्ञात कीजिए ।

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MPPGCL JE Electrical 19 March 2019 Shift 2 Official Paper

Answer 1

संप्रत्यय

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मान लीजिए कि नोड 'a' पर वोल्टेज V_a है

$\frac{V_{a} + 12}{10} - 3 + \frac{V_{a} - 8}{40} = 0$

$\frac{V_{a} + 12}{10} + \frac{V_{a} - 8}{40} = 3$

$\frac{4 V_{a} + 48 + V_{a} - 8}{40} = 3$

$4 V_{a} + 48 + V_{a} - 8 = 120$

$5 V_{a} = 120 - 48 + 8$

Va = 16 V