Question
Download Solution PDFएक 40 kVA ट्रांसफॉर्मर में कोर लॉस 400 W व फुल लोड कॉपर लॉस 800 W है। अधिकतम क्षमता में कितना हिस्सा फुल लोड का होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
1ϕ ट्रांसफार्मर में अधिकतम दक्षता की शर्त निम्न है:
PC = (x)2Pcufl
जहाँ, PC = कोर नुकसान
Pcufl = पूर्ण भार पर ताम्र नुकसान
x = भारण का भिन्न
गणना:
दिया गया है, PC = 400 W
Pcufl = 800 W
400 = (x)2 × 800
\(x = \sqrt{400 \over 800}\)
x = 70.7%
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