Differentiate cos (sin x) with respect to x:

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. −sin x ⋅ cos (cos x)
  2. −cos x ⋅ sin (sin x)
  3. cos x ⋅ sin (sin x)
  4. sin x ⋅ cos (sin x)

Answer (Detailed Solution Below)

Option 2 : −cos x ⋅ sin (sin x)
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Bihar STET Paper 1 Mathematics Full Test 1
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Detailed Solution

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Given:

f(x) = cos(sin(x))

Concept used:

The chain rule states that if you have a composition of functions, like f(g(x)), the derivative is f′(g(x)) × g′(x).

Calculation:

⇒ f(u) = cos(u)

⇒ f'(u) = -sin(u) (derivative of cos(u))

⇒ g(x) = sin(x)

⇒ g'(x) = cos(x) (derivative of sin(x))

\(\dfrac{d}{dx}\)[cos(sin(x))] = f'(g(x)) × g'(x)

\(\dfrac{d}{dx}\)[cos(sin(x))] = -sin(sin(x)) × cos(x)

∴ The derivative of cos(sin(x)) with respect to x is −cos x ⋅ sin (sin x)

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