Question
Download Solution PDFযদি একটি গোলকের আয়তন 24,416.64 সেমি3 হয়, তাহলে এর পৃষ্ঠের ক্ষেত্রফল (π = 3.14 ধরে নিয়ে) দশমিকে নির্ণয় করুন।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
একটি গোলকের আয়তন 24,416.64 সেমি3
অনুসৃত ধারণা:
গোলকের আয়তন = 4/3πr3
গোলকের পৃষ্ঠের ক্ষেত্রফল = 4πr2
এখানে,
r = ব্যাসার্ধ
গণনা:
4/3πr3 = 24416.64
⇒ r3 = 24416.64 × (3/4) × 1/3.14
⇒ r3 = 5832
⇒ r = 18
এখন,
পৃষ্ঠের ক্ষেত্রফল = 4 × 3.14 × 182
⇒ 12.56 × 324
⇒ 4069.44 সেমি2
∴ গোলকের পৃষ্ঠের নির্ণেয় ক্ষেত্রফল 4069.44 সেমি2.
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