Question
Download Solution PDFA rectangular waveguide has dimensions 1 cm × 0.5 cm. Its cut off frequency is :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The cut-off frequency of a rectangular waveguide in dominant TE10 mode is given by:
\( f_c = \frac{c}{2a} \), where:
c = speed of light = \( 3 \times 10^8~m/s \), and a = broader dimension of the waveguide
Calculation:
Given:
Dimensions of waveguide = 1 cm × 0.5 cm
So, a = 1 cm = 0.01 m
Using the formula, \( f_c = \frac{3 \times 10^8}{2 \times 0.01} \)
\( f_c = \frac{3 \times 10^8}{0.02} = 1.5 \times 10^{10}~Hz = 15~GHz \)
Correct Answer: 2) 15 GHz
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