Question
Download Solution PDFA and B together complete a work in 24 days, A alone complete the work in 60 days. C takes 10 days less than the B takes to complete the work alone. Find the time taken by A, B and C together to complete 3/4th part of the work?
Answer (Detailed Solution Below)
Detailed Solution
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A and B together = 1/24 per day
A = 1/60 ⇒ B = 1/24 − 1/60 = (5−2)/120 = 3/120 = 1/40
Let C takes x days, so B = x days, C = x − 10 ⇒ C = 1/(x−10)
B = 1/x = 1/40 ⇒ x = 40 ⇒ C = 30
So A = 1/60, B = 1/40, C = 1/30
Total work in 1 day = LCM(60,40,30) = 120
Work/day = 2 + 3 + 4 = 9 units/day
3/4 work = 90 units
Time = 90/9 = 10 days
Last updated on Jun 17, 2025
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