Linear Equation in 1 Variable MCQ Quiz - Objective Question with Answer for Linear Equation in 1 Variable - Download Free PDF

Given:

Equation: 12p – 11 = 13

Calculations:

12p – 11 = 13

⇒ 12p = 13 + 11

⇒ 12p = 24

⇒ p = 24 ÷ 12

⇒ p = 2

∴ The correct answer is option (2).

Given:

Equation: 10y - 20 = 30

Calculation:

10y - 20 = 30

⇒ 10y = 30 + 20

⇒ 10y = 50

⇒ y = 50 ÷ 10

⇒ y = 5

∴ The correct answer is option (4).

Given:

Equation: 4p - 2 = 10

Calculations:

4p - 2 = 10

⇒ 4p = 10 + 2

⇒ 4p = 12

⇒ p = 12 ÷ 4

⇒ p = 3

∴ The correct answer is option (3).

Calculation:

Let's assume total number of trees in the garden is = LCM of (5, 2) = 10 unit

So, the number of mango trees = 10 × 1/5 = 2 unit

The number of Ashoka trees = 10 × 1/2 = 5 unit

So, the number of neem trees = 10 - (5 + 2) = 3 unit

Now, according to the question,

3 unit → 12

then, mango trees 2 unit → 12/3 × 2 = 8

∴ The correct answer is 8

Deatialed solution:-

Let the number of students in the class be ‘x’

No. of chocolates received by each student = 2x

Total number of chocolates = 2x × x

⇒ 2x² = 1800

⇒ x² = 900

⇒ x = √900 = 30

GIVEN :

Four times the first number is 10 more than thrice the second number.

CALCULATION :

Suppose the numbers are ‘a’ and ‘a + 1’.

According to the question :

4a = 3 × (a + 1) + 10

⇒ a = 13

Hence, the numbers are 13 and 14.

Let the present age be x

⇒ Six years ago my age will be = (x - 6)

⇒ Age after 10 years = (x + 10)

According to the question

⇒ 80% of (x – 6) = 60% of (x + 10)

⇒ 4x – 24 = 3x + 30

⇒ x = 54

∴ Product of digits = 5 × 4 = 20

Given:

500 + 1 holiday = 7 weeks      ----(1)

50 + 1 holiday = 5 weeks      ----(2)

⇒ From (1) - (2)

450 = 2 weeks

⇒ 1 week = 225 Rs.

From (1),

⇒ 500 + 1 holiday = 7 × 225

⇒ 1 holiday = 1575 - 500

Calculation:

Let the lottery worth be Rs. x

Winning amount = $\frac{x}{3}$

Donated amount $=6000=\frac{x}{3}\times \frac{1}{6}$

Given:

Total grains = 50 kg, price = Rs. 710

Price of rice per kg = Rs. 12

Price of wheat per kg = Rs. 17

Calculation:

Let Ashish purchased x kg of rice

So, quantity of wheat he purchased = (50 – x)

Now,

⇒x × 12 + (50 – x) × 17 = 710

⇒ 12x + 850 – 17x = 710

⇒ 5x = 140

⇒ x = 28 kg

∴ Money spent on rice = 12 × 28 = Rs. 336

Given:

Ratio of monthly incomes of Ravi and Shiv = 1 : 2

Ratio of monthly expenditures = 1 : 3

Savings per month each = Rs 4,000

Concept Used:

Income – Savings = Expenditure

Calculation:

⇒ Let the monthly incomes of Ravi and Shiv be x and 2x.

⇒ According to the question,

⇒ $\frac{x-4000}{2x-4000}=\frac{1}{3}$

⇒ 3(x – 4000) = 1(2x – 4000)

⇒ 3x – 12000 = 2x – 4000

⇒ 3x – 2x = 12000 – 4000

⇒ x = 8000

⇒ Income of Shiv = 2x = 2 × 8000 = Rs 16,000

Therefore, the monthly income of Shiv is Rs 16,000.

Let the total worth of land is Rs. X

⇒ Given, 9x/7 = 10116

⇒ So, x = 7868

Given:

1/3^rd of the first of the three consecutive odd numbers is 2 more than 1/5^th of the third number.

Calculation:

Let, the three consecutive odd numbers be x, x + 2 and x + 4 respectively, then

According to the question,

x × (1/3) = (x + 4) × (1/5) + 2

⇒ x/3 = (x + 4 + 10)/5

⇒ 5x = 3x + 42

⇒ 5x – 3x = 42

⇒ 2x = 42

⇒ x = 21

∴ Second odd number is x + 2 = 21 + 2 = 23 

Given y² = y + 7

Multiplying LHS and RHS by y

⇒ y³ = y² + 7y

∴ y³ = y + 7 + 7y = 8y + 7 [∵ y² = y + 7]

GIVEN:

x² - 7x + 1 = 0

CALCULATION:

x² - 7x + 1 = 0

Dividing by x:

⇒ x - 7 + 1/x = 0

⇒ x + 1/x = 7