Average Speed MCQ Quiz - Objective Question with Answer for Average Speed - Download Free PDF
Last updated on Jun 10, 2025
Latest Average Speed MCQ Objective Questions
Average Speed Question 1:
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of the flight increased by 30 minutes. The duration of the flight is
Answer (Detailed Solution Below)
Average Speed Question 1 Detailed Solution
Given:
Total Distance = 600 km.
average speed was reduced = 200 km/hr
the time of flight increased = 30 minutes
Formula Used:
∵ Average Speed = Total Distance / Time
Calculations:
Let, the original duration of flight be t hrs.
So, original average speed = 600/t
Due to bad weather speed of trip is reduced by 200 km/hr and time of flight is increased by 30 minutes i.e. 0.5 hr.
∴ Reduced average speed = (600/t) – 200
And New duration of flight = (t + 0.5) hrs
So, the new average speed = 600/(t + 0.5)
Equating,
\(\begin{array}{l} \Rightarrow \frac{{600}}{t}-200 = \frac{{600}}{{t + 0.5}}\\ \Rightarrow \frac{3}{t}-1 = \frac{3}{{t + 0.5}}\\ \Rightarrow \frac{{3-t}}{t} = \frac{3}{{t + 0.5}} \end{array}\)
⇒ t2 + 0.5t – 1.5 = 0
⇒ 2t2 + t – 3 = 0
⇒ 2t2 – 2t + 3t – 3 = 0
⇒ (t – 1)(2t + 3) = 0
⇒ (t – 1) = 0
∴ t = 1 hr
∴ The duration of the flight is 1 hr.
Average Speed Question 2:
Q completes a journey in 99 hours. She travels first half of the journey at the rate of 96 kmph and second half at the rate of 102 kmph. Find the total distance (in km).
Answer (Detailed Solution Below)
Average Speed Question 2 Detailed Solution
Given:
Q completes a journey in 99 hours.
First half of the journey is traveled at 96 kmph.
Second half of the journey is traveled at 102 kmph.
Formula used:
Total time = Time for first half + Time for second half
Time = Distance ÷ Speed
Let the total distance be D, so the first half = D/2 and second half = D/2.
Total time = (D/2 ÷ 96) + (D/2 ÷ 102)
Calculation:
Total time = 99 hours
⇒ \(\dfrac{D}{2 \times 96} + \dfrac{D}{2 \times 102} = 99\)
⇒ \(\dfrac{D}{192} + \dfrac{D}{204} = 99\)
⇒ Take LCM of 192 and 204: LCM = 3264
⇒ \(\dfrac{17D}{3264} + \dfrac{16D}{3264} = 99\)
⇒ \(\dfrac{33D}{3264} = 99\)
⇒ \(\dfrac{D}{99} = \dfrac{3264}{33}\)
⇒ D = \(\dfrac{3264 \times 99}{33}\)
⇒ D = 9792
∴ The total distance is 9792 km, and the correct answer is option (4).
Average Speed Question 3:
A car travels 281 km in the first hour and 163 km in the second hour. What is the average speed (in km/h) of the car for the whole journey?
Answer (Detailed Solution Below)
Average Speed Question 3 Detailed Solution
Given:
Distance in 1st hour = 281 km
Distance in 2nd hour = 163 km
Total time = 2 hours
Formula used:
Average speed = Total distance ÷ Total time
Calculation:
Total distance = 281 + 163 = 444 km
Total time = 2 hours
⇒ Average speed = 444 ÷ 2 = 222 km/h
∴ The average speed is 222 km/h.
Average Speed Question 4:
In a race, an athlete covers a distance of 300 m in 50 sec in the first lap. He covers the second lap of the same length in 150 sec. What is the average speed (in m/sec) of the athlete?
Answer (Detailed Solution Below)
Average Speed Question 4 Detailed Solution
Given:
Distance of first lap = 300 m
Time for first lap = 50 sec
Distance of second lap = 300 m
Time for second lap = 150 sec
Formula used:
Average speed = Total distance / Total time
Calculation:
Total distance = 300 + 300 = 600 m
Total time = 50 + 150 = 200 sec
⇒ Average speed = 600 / 200
⇒ Average speed = 3 m/sec
∴ The correct answer is option (2).
Average Speed Question 5:
A girl goes to school at a speed of 10 km/hr. She comes back with a speed of 40 km/hr. Find her average speed for the whole journey.
Answer (Detailed Solution Below)
Average Speed Question 5 Detailed Solution
Given:
Speed while going to school (S1) = 10 km/h
Speed while coming back (S2) = 40 km/h
Formula used:
Average Speed = \(\dfrac{2 \times S_1 \times S_2}{S_1 + S_2}\)
Calculation:
Average Speed = \(\dfrac{2 \times 10 \times 40}{10 + 40}\)
⇒ Average Speed = \(\dfrac{2 \times 400}{50}\)
⇒ Average Speed = \(\dfrac{800}{50}\)
⇒ Average Speed = 16 km/h
∴ The correct answer is option (3).
Top Average Speed MCQ Objective Questions
A man travels from A to B at a speed of 36 km/hr in 74 minutes and he travels a distance from B to C with a speed of 45 km/hr in 111 minutes. Find the average speed of whole journey.
Answer (Detailed Solution Below)
Average Speed Question 6 Detailed Solution
Download Solution PDFGiven:
A man travels from A to B at a speed of 36 km/hr in 74 minutes and he travels a distance from B to C with a speed of 45 km/hr in 111 minutes.
Formula used:
Average speed = Total distance/Total time taken
Calculation:
Time taken = 74 min : 111 min [given]
Ratio of Time taken = 2 : 3
Average Speed = \(\frac{{36\ \times\ 2\ +\ 45\ \times\ 3}}{{2\ +\ 3}}\)
Average Speed = 207/5
Average Speed = 41.4 km/hr
∴ The average speed of whole journey is 41.4 km/h
As part of his journey, a person travels 120 km at 80 km/h, the next 100 km at 40 km/h, and comes back to the starting point at 75 km/h. The average speed of the person throughout the journey (approximately) is:
Answer (Detailed Solution Below)
Average Speed Question 7 Detailed Solution
Download Solution PDFGiven:
A person travels 120 km at 80 km/h, the next 100 km at 40 km/h, and comes back to the starting point at 75 km/h
Formula used:
Average speed = total distance/total time
Calculation:
Average speed = total distance/total time
Total distance = 120 + 100 + 220
= 440 km
Total time = (120/80) + (100/40) + (220/75)
= (3/2 + 5/2 + 44/15)
= (45 + 75 + 88)/30
= 208/30
Average speed = 440/(208/30)
= (440 * 30) / 208
= 63.46 km/hr
∴ The average speed is 63.46 km/hr.
Mohan goes to office from home at a speed of 20 km/h and returns to home from office at a certain speed. If the average speed is 24 km/h, then what is the speed while returning?
Answer (Detailed Solution Below)
Average Speed Question 8 Detailed Solution
Download Solution PDFGiven
Speed from home to office = 20 km/h
Average speed = 24 km/h
Concept:
Let the speed while returning from the office to home be denoted by x. We can use the concept of average speed to set up an equation and solve for x.
Solution:
The formula for average speed is given by:
Average speed = 2ab/(a + b)
where a and b are the speeds of two different segments.
Using the given data, we have:
24 km/h = (2 × 20 km/h × x)/(20 km/h + x)
Simplifying this equation, we find:
480 km/h + 24x km = 40x km/h
16x = 480
x = 30 km/h
Therefore, the speed while returning is 30 km/h.
One person travels on through the sides of an equilateral triangle at a speed of 12 kmph, 24 kmph, and 8 kmph. Find the average speed of it. (In kmph)
Answer (Detailed Solution Below)
Average Speed Question 9 Detailed Solution
Download Solution PDFGiven:
The speed of the man is 12 km/h, 24 km/h and 8 km/h
Concept Used:
Average speed = total distance/total time
The sides of an equilateral triangle are equal.
Calculation:
Let, the side of the triangle be x km.
As we know,
Time to cover x km distance at a speed of 12 km/hr = x/12 hrs
Time to cover x km distance at a speed of 24 km/hr = x/24 hrs
Time to cover x km distance at a speed of 8 km/hr = x/8 hrs
Total distance covered by the man = (x + x + x) = 3x
Total time to cover the distance (x/12 + x/24 + x/8)
∴ Average speed \( = \frac{{3x}}{{\frac{x}{{24}} + \frac{x}{{12}} + \frac{x}{8}}}\)
⇒ \(\frac{{3x}}{{\frac{{x + 2x + 3x}}{{24}}}}\)
⇒ 3x / (6x/24)
⇒ 1/2 × 24 = 12 kmph
∴ The average speed of the person is 12 km/h.
A car covers a distance of 48 km at a speed of 40 km/h and another 52 km with a speed of 65 km/h. What is the average speed of the car (in km/h) for the total distance covered?
Answer (Detailed Solution Below)
Average Speed Question 10 Detailed Solution
Download Solution PDFGiven:
Speed1 = 40 km/h, Distance1 = 48 km
Speed2 = 65 km/h, Distance2 = 52 km
Formula used:
Time = Distance/ Speed
Average Speed = Total Distance/ Total Time
Calculation:
Total Distance traveled = 48 km + 52 km
⇒ 100 km
Total Time = 48 km/ 40 km/h + 52 km/ 65 km/h
⇒ 6/5 + 4/5 = 2 hours
Average Speed = 100 km/ 2 hours
∴ The required Speed = 50 km/h
A car travel first 33 minutes with a speed of 60 km/h, again 33 minutes with a speed of 70 km/h, then find the average speed of the car during the whole journey.
Answer (Detailed Solution Below)
Average Speed Question 11 Detailed Solution
Download Solution PDFGiven:
A car travels first 33 minutes with a speed of 60 km/h,
Again 33 minutes with a speed of 70 km/h
Concept used:
Distance = velocity × time
Average speed = (Total distance)/(Total time)
Calculation:
\(\)\({\rm{Average\;speed}} = {\rm{\;}}\frac{{\frac{{33}}{{60}}\: ×\:60\: + \:\frac{{33}}{{60}}\: ×\: 70}}{{\frac{{66}}{{60}}}}\)
⇒ Average speed = (33 × 60 + 33 × 70)/66
⇒ Average speed = (60 + 70)/2 = 65 km/h
∴ The average speed of car is 65 km/h.
Shortcut Trick
Concept:
When the time interval is the same for equal distances then,
Average speed = (v1 + v2)/2
where v = velocity
Calculation:
Average speed = (70 + 60)/2 = 65 km/h
∴ The average speed of the car is 65 km/h.
Two trains, X and Y, travel from A to B at average speeds of 80 km/hr and 90 km/hr respectively. If X takes an hour more than Y for the journey, then the distance between A and B is _____.
Answer (Detailed Solution Below)
Average Speed Question 12 Detailed Solution
Download Solution PDFGiven:
Two trains, X and Y, travel from A to B at average speeds of 80 km/hr and 90 km/hr respectively.
Formula:
Speed = distance/time
Calculation:
Let distance be x km
According to the question
x/80 – x/90 = 1
⇒ (9x – 8x)/720 = 1
⇒ x = 720 km
A person goes from A to B with speed 40 km/hr & return from B to A with speed 30 km/hr. Whole journey takes 14 hr, then find the distance between A & B in Km.
Answer (Detailed Solution Below)
Average Speed Question 13 Detailed Solution
Download Solution PDFFormula used:
Distance = Speed × Time
Calculation:
Let the distance be ‘D’ km
According to the question,
D/40 + D/30 = 14
⇒ (3D + 4D)/120 = 14
⇒ 7D/120 = 14
⇒ D = 240 km
∴ Distance between A & B = 240 km
Alternate Method
Formula used:
Average Speed = 2ab/(a + b)
Calculation:
Let the distance be ‘D’ km
Vav = (2 × 40 × 30)/(40 + 30)
⇒ Vav = 240/7 km/hr
Since person cover (D + D) i.e. 2D & it take 14 hr
⇒ 2D/14 = 240/7
⇒ D = 240 km
Confusion Points
Average Speed = (a + b)/2
Applicable when one travels at speed a for half the time and speed b for another half of the time.
A man covers a certain distance by scooter at 64 km/h and he returns to the starting place riding a bicycle at 16 km/h. Find the average speed for the whole journey.
Answer (Detailed Solution Below)
Average Speed Question 14 Detailed Solution
Download Solution PDFGiven:
A man covers a certain distance on a scooter driving at 64 km/h.
He returns to the starting point riding on a bicycle at 16 km/h.
Formula used:
Formula:
Average speed = 2s1s2/(s1+s2)
Solution:
Average speed = 2s1s2/(s1+s2)
(2 × 64 × 16)/(64 + 16)
25.6 km/h
∴ The answer is 25.6 km/h.
Ram covered 60 km in a bus in 50 minute, after deboarding the bus, he took rest for 5 min. There after he took a taxi to his home 30 km away and reached in 20 min. find his average speed in km/h.
Answer (Detailed Solution Below)
Average Speed Question 15 Detailed Solution
Download Solution PDFGIVEN:
Ram covered 60 km in a bus in 50 min. after deboarding the bus, he took rest for 5 min. There after he took a taxi to his home 30 km away and reached in 20 min.
CONCEPT:
Basic concept of time speed and distance.
FORMULA USED:
Average speed = Total distance/Total time taken
CALCULATION:
Total distance = 60 + 30 = 90 km
Total time taken = 50 + 5 + 20 = 75 min = 5/4 hr
Hence,
Average speed = 90/(5/4) = 72 km/h