Greatest Integer Functions MCQ Quiz in বাংলা - Objective Question with Answer for Greatest Integer Functions - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Mar 15, 2025

পাওয়া Greatest Integer Functions उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Greatest Integer Functions MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Greatest Integer Functions MCQ Objective Questions

Top Greatest Integer Functions MCQ Objective Questions

Greatest Integer Functions Question 1:

Let [.] denote the greatest integer function. If \(\int_{0}^{3} \left[ \frac{1}{e^{x-1}} \right] dx = \alpha - \log_e 2, \text{ then } \alpha^3 \text{ is equal to } \_\_\_\_.\)

Answer (Detailed Solution Below) 0 - 8

Greatest Integer Functions Question 1 Detailed Solution

Concept:

Greatest Integer Function and Definite Integral:

The greatest integer function, denoted by [x], gives the greatest integer less than or equal to x.

When integrating a function involving the greatest integer function, it is important to break the integral over intervals where the floor value is constant.

Given integral:

\(\displaystyle \int_0^3 \left[ \frac{1}{e^{x-1}} \right] dx = \int_0^3 \left[ e^{1-x} \right] dx = \alpha - \log_e 2 \)

Calculation

 \((f(x) = 2, e^{1-x} = 2 \Rightarrow x = 1 - \ln 2.\)

 \((f(x) = 1, (e^{1-x} = 1 \Rightarrow x = 1\)

Also 

f(0) = e1-0 = e ≈2.718 > 2

f(1) = e1 =0

f(2) = e-1 = 0.367

f(3) = e-2 = ≈ 0.1353

\[ \int_0^3 [f(x)] \, dx = \int_0^{1-\ln 2} 2 \, dx + \int_{1-\ln 2}^1 1 \, dx + \int_1^3 0 \, dx \]

\[ = 2(1-\ln 2) + (1 - (1-\ln 2)) + 0 = 2 - 2\ln 2 + \ln 2 = 2 - \ln 2 \]

Also

\[ \int_0^3 [f(x)] \, dx = \alpha - \log_e 2 \]

Comparing,

\[ 2 - \ln 2 = \alpha - \ln 2 \implies \alpha = 2 \]

Therefore,

\[ \alpha^3 = 2^3 = 8 \]

∴ The value of α3" id="MathJax-Element-185-Frame" role="presentation" style="position: relative;" tabindex="0">α3" id="MathJax-Element-138-Frame" role="presentation" style="position: relative;" tabindex="0">α3" id="MathJax-Element-150-Frame" role="presentation" style="position: relative;" tabindex="0">α3 is 8.

Greatest Integer Functions Question 2:

Consider the function f(x) = [x + 1] - (sin\(\frac{\pi }{2}\)[x]) for x ϵ R. where [x] denotes the greatest integer less than or equal to x. Let l1 = limx→0-f(x) and l2 = limx→0+ f(x).It follows that

  1. \(l_1=l_2=1\)
  2. \(l_1=l_2=-1\)
  3. \(l_1=-1;l_2=1\)
  4. \(l_1=1;l_2=-1\)

Answer (Detailed Solution Below)

Option 1 : \(l_1=l_2=1\)

Greatest Integer Functions Question 2 Detailed Solution

Concept :

⇒ f(x) = [x] denotes a step function whose graph is as follows :

F1 Ravi Sharma Anil 12-06.21 D29

⇒ Thus by the graph we can depict any value, for example [2.93] = 2, [-0.5] = -1, ...

 

Calculation :

Given the function f(x) = [x + 1] - (sin\(\frac{π }{2}\)[x]).

It is given that l= limx→0-f(x).

⇒ l= limx→0-f(x) =  limx→0- {[x + 1] - (sin\(\frac{π }{2}\)[x])} = {[0-+1] - (sin\(\frac{π }{2}\)[0-])} = {[1-] - (sin\(\frac{π }{2}\)[0-])}.

⇒ l= {[1-] - (sin\(\frac{-π }{2}\))} = {0- (-1)} = 1.

It is given that l2 = limx→0+f(x).

⇒ l2 = limx→0+f(x) =  limx→0+ {[x + 1] - (sin\(\frac{π }{2}\)[x])} = {[0++1] - (sin\(\frac{π }{2}\)[0+])} = {[1+] - (sin\(\frac{π }{2}\)[0+])}.

⇒ l2 = {[1+] - (sin(0))} = {1- 0} = 1.

Thus ll2 = 1.

Mistake Points

Student often gets mistaken in two points when solving these type of problems :

  1. Observation and representation of step bracket wherever necessary.
  2. sin\(\frac{π }{2}\)(0-) = sin\(\frac{π }{2}\)(0+) = 0, but their Difference when a step function is used on them.

       ⇒ sin\(\frac{π }{2}\)[0-] = sin\(\frac{-π }{2}\) = -1 and sin\(\frac{π }{2}\)[0+] = sin0 = 0.

Greatest Integer Functions Question 3:

If f(x) = (x)[x] where [.] denotes greatest integer function and g(x) = x2 then find the value of g o f(5/2) ?

  1. 125/16
  2. 25/16
  3. 625/16
  4. None of these

Answer (Detailed Solution Below)

Option 3 : 625/16

Greatest Integer Functions Question 3 Detailed Solution

Concept:

Greatest Integer Function: (Floor function)

The function f (x) = [x] is called the greatest integer function and means greatest integer less than or equal to x i.e [x] ≤ x.

Domain of [x] is R and range is I.

If f :A → B and g : C → D. Then (fog) (x) will exist if and only if co-domain of g = domain of f i.e D = A and (gof) (x) will exist if and only if co-domain of f = domain of g i.e B = C.

Calculation:

Given: f(x) = (x)[x] where [.] denotes greatest integer function and g(x) = x2 

Here, we have to find the value of g o f(5/2) 

⇒ g o f(5/2)  = g( f(5/2))

∵ f(x) = (x)[x] where [.] denotes greatest integer function

⇒ f(5/2) = (5/2)[5/2]

As we know that [5/2] = 2

⇒ f(5/2) = (5/2)2 = 25/4

⇒ g o f(5/2)  = g(25/4)

∵ g(x) = x2 so, g(25/4) = 625/16

Hence, g o f(5/2) = 625/16

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