Which one of the following options is incorrect? 

For a square matrix A in the matrix equation AX = B. 

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CUET UG Official Maths Paper (Held on_23 May 23)
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  1. If |A| ≠ 0, then there exists a unique solution 
  2. If |A| = 0 and (adj A)B ≠ 0 then there is no solution 
  3. If |A| ≠ 0 and (adj A)B ≠ 0 then there is no solution 
  4. If |A| = 0 and (adj A)B = 0 then system has infinitely many solutions 

Answer (Detailed Solution Below)

Option 3 : If |A| ≠ 0 and (adj A)B ≠ 0 then there is no solution 
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Detailed Solution

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Explanation:

Matrix equation is Ax = B where A is square matrix and B is column matrix.

Then if |A| ≠ 0, then there exists a unique solution.

If |A| = 0 and (adj A)B ≠ 0 then there is no solution i.e., inconsistent. 

If |A| = 0 and (adj A)B = 0 then system has infinitely many solutions i.e., consistent.

Hence the incorrect statement is "If |A| ≠ 0 and (adj A)B ≠ 0 then there is no solution."

Option (3) is true. 

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