Question
Download Solution PDFWhat is value of \(\rm \int_{-\pi/2}^{\pi/2} x^{5}\sin^{4}x dx\) ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The rules for integrating even and odd functions ,
If the function is even or odd and the interval is [-a, a], we can apply these rules:
- When f(x) is even ⇔ \(\rm\int_{-a}^{a}f(x)dx= 2 \int_{0}^{a}f(x)dx\)
- When f(x) is odd ⇔ \(\rm\int_{-a}^{a}f(x)dx= 0\)
Calculation:
Let f (x) = x5 sin4 x
f (-x) = (-x)5 sin4 (-x) = -x5 (-sin x )4 = -x5 sin4 x .
⇒ f(-x) = - f(x)
So, f(x) is an odd function .
We knoiw that, when f(x) is odd ⇔ \(\rm\int_{-a}^{a}f(x)dx= 0\)
Hence , \(\rm \int_{-\pi/2}^{\pi/2} x^{5}\sin^{4}x dx\) = 0 .
The correct option is 4 .
Last updated on Jun 18, 2025
->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.