What is the sum of the numbers which is fourth from the left end in step II and fourth from the right in the last step?

The logic is as follows:

Step I: The first two smallest numbers are arranged in ascending order.

Step II: The next two smallest numbers are arranged in ascending order shifting the previously arranged one inward.

Step III: The digits of all the numbers are interchanged

Step IV: Taking a pair of numbers from the left-most side, the first two digits of the number pair are taken to form a number. Similarly, the second two digits of a number pair are taken to form the next number.

Input: 12  46  32  11  19  36  89  41  56  53  75  81

Step I: 11  12 46  32  19  36  89  41  56  53  75  81  

Step II: 19  32  11  12  46  36  89  41  56  53  75  81

Step III: 91  23  11  21  64  63  98  14  65  35  57  18

Step IV: 92  13  12  11  66  43  91  84  63  55  51  78

Thus, Step IV is the last step.

The number which is fourth from the left end in step II = 12

The number which is fourth from the right end in step IV = 65

Sum = 12 + 63 = 75

Hence, 75 is the correct answer.