Two vessels A and B contain a mixture of alcohol and water such that A contains 25% alcohol and B contains 15% alcohol. Some part of the mixture in vessel A is replaced by an equal quantity of mixture from vessel B. How much quantity of the mixture was replaced if the final mixture vessel is 18% alcohol?

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Given:

Quantity of alcohol in vessel A = 25%

Quantity of alcohol in vessel B = 15%

Quantity of alcohol in mixture = 18%

Concept used:

Calculations:

So, the ratio is 3 ∶ 7

So, Replaced part = 

∴ The quantity of the mixture was replaced in .

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