Question
Download Solution PDFThe total number of numbers that can be formed by using the digits 5, 3 and 7 only, if no repetitions are allowed, is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Basic Principle of Counting:
If there are m ways for happening of an event A, and corresponding to each possibility there are n ways for happening of event B, then the total number of different possibilities for happening of events A and B are:
- Either event A alone OR event B alone = m + n.
- Both event A AND event B together = m × n.
Calculation:
Since, the repetition is not allowed, we cannot form a four-digit or a higher digit number.
We have the following possible cases:
One-digit number:
There are three possibilities (3, 5, 7) for the single digit. ⇒ 3 possibilities.
Two-digit number:
There are three possibilities for one of the digits, and corresponding to each possibility, the other digit will have two possibilities. ⇒ 3 × 2 = 6 possibilities.
Three-digit number:
There are three possibilities for one of the digits, and then two possibilities for the second digit and then only a single possibility for the third digit. ⇒ 3 × 2 × 1 = 6 possibilities.
∴ The total number of possible numbers = 3 + 6 + 6 = 15.
Last updated on Jun 12, 2025
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