The sum of the radius of the base and the height of a solid right circular cylinder is 39 cm. Its total surface area is 1716 cm2. What is the volume (in cm3) of the cylinder? (Take π = \(\frac{22}{7}\))

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RRB NTPC CBT 2 (Level-5) Official Paper (Held On: 15 June 2022 Shift 2)
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  1. 4774
  2. 5082
  3. 4928
  4. 4620

Answer (Detailed Solution Below)

Option 3 : 4928
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RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
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Detailed Solution

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Given:

Sum of radius and height of the cylinder = 39 cm

Total surface area of the cylinder = 1716 cm2

Concept used:

Total surface area of a cylinder = 2πr(h + r)

Volume = πr2h

Here,

r = radius

h = height

Calculation:

Let the radius and the height of the cylinder be r and h,

According to the question,

2πr(h + r) = 1716      ----(i)

(h + r) = 39      ----(ii)

Putting the value of eq (ii) in eq (i) we get,

2πr × 39 = 1716

⇒ 2πr = 1716/39

⇒ 2πr = 44

⇒ πr = 22

⇒ r = 22 × (7/22)

⇒ r = 7

So, radius = 7 cm

Now, by putting the value of r in the eq (ii) we get

h + 7 = 39

⇒ h = 32

So, height = 32 cm

Now, volume = (22/7) × 72 × 32

⇒ 22 × 7 × 32

⇒ 4928

So, volume of the cylinder = 4928 cm3

∴ The volume (in cm3) of the cylinder i 4928.

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