The peak factor of a half - wave rectified sine wave is _______.

This question was previously asked in
PGCIL DT Electrical 5 May 2023 Official Paper
View all PGCIL Diploma Trainee Papers >
  1. 1.41
  2. 1.11
  3. 1.57
  4. 2.00

Answer (Detailed Solution Below)

Option 4 : 2.00
Free
PGCI DT EE Power System Mock Test
6 K Users
20 Questions 20 Marks 15 Mins

Detailed Solution

Download Solution PDF

Concept:

The peak factor is defined as the ratio of the maximum value to the RMS value of an alternating quantity.

Peak factor = Peak value / RMS value

RMS voltage of a half-wave rectifier,

VRMS = Vm/2

Where Vm is the Maximum or peak voltage.

Then the Peak factor of half wave rectifier can be calculated as,

Vm / VRMS = Vm / ( Vm / 2 ) = 2 Vm / Vm = 2
 Additional Information 

Similarly, For a full wave rectifier,

The RMS voltage → VRMS = Vm / √2

Therefore,

The Peak factor value of the full wave rectifier = Vm / Vm/ √2 = Vm √2 / Vm = √2 = 1.414

Latest PGCIL Diploma Trainee Updates

Last updated on May 9, 2025

-> PGCIL Diploma Trainee result 2025 will be released in the third week of May. 

-> The PGCIL Diploma Trainee Answer key 2025 has been released on 12th April. Candidates can raise objection from 12 April to 14 April 2025.

-> The PGCIL DT Exam was conducted on 11 April 2025. 

-> Candidates had applied online from 21st October 2024 to 19th November 2024.

-> A total of 666 vacancies have been released.

-> Candidates between 18 -27 years of age, with a diploma in the concerned stream are eligible.

-> Attempt PGCIL Diploma Trainee Previous Year Papers for good preparation.

More Diodes and Its Applications Questions

Get Free Access Now
Hot Links: teen patti joy 51 bonus teen patti master teen patti real cash teen patti boss