The maximum load allowed in 

\(\rm \frac{power\ sub\ circuit}{light\ fan\ sub\ circuit}=?\)

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PGCIL DT Electrical 12 March 2022 (NR II) Official Paper
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  1. \(\frac{30}{8}\)
  2. \(\frac{80}{3}\)
  3. \(\frac{3}{8}\)
  4. \(\frac{8}{3}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{30}{8}\)
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Detailed Solution

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The correct answer is option 1):\(\frac{30}{8}\)

Concept:

Power subcircuit:

  • The maximum load for the power sub-circuit should not exceed 3000 W
  • The number of outlets is restricted to two in each power subcircuit. If the power load exceeds 3000 W, a separate power circuit is taken

Light and Fan sub-circuits:

  • There is a maximum of 10 points in the light and fan sub-circuit as per IE (Indian Electricity) rules.
  • The maximum load for a single light and fan sub-circuit should not exceed 800 W.

\(\rm \frac{power\ sub\ circuit}{light\ fan\ sub\ circuit}=\) \(3000 \over 800\) = \(30 \over 8\)

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