Question
Download Solution PDFThe incident matrix of a graph is given below:
a | b | c | d | e | f | |
1 | +1 | 0 | +1 | 0 | 0 | +1 |
2 | -1 | -1 | 0 | +1 | 0 | 0 |
3 | 0 | +1 | 0 | 0 | +1 | -1 |
4 | 0 | 0 | -1 | -1 | -1 | 0 |
The corresponding graph is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- The no. of rows in an incident matrix determines the total no. of nodes present in a graph.
- The no. of columns in an incident matrix determines the total no. of branches present in a graph.
- The incoming arrow to a node is taken as -1.
- The outgoing arrow to a node is taken as +1.
Explanation:
a | b | c | d | e | f | |
1 | +1 | 0 | +1 | 0 | 0 | +1 |
2 | -1 | -1 | 0 | +1 | 0 | 0 |
3 | 0 | +1 | 0 | 0 | +1 | -1 |
4 | 0 | 0 | -1 | -1 | -1 | 0 |
Following are the results from the above incident matrix:
No. of rows = 4 = Total no. of nodes
No. of columns = 6 = Total no. of branches
Node 1: Three outgoing arrows
Node 2: Two incoming and one outgoing arrow
Node 3: One incoming and two outgoing arrows
Node 4: Three incoming arrows
All the above conditions are fulfilled by option 2.
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