The incident matrix of a graph is given below:

  a b c d e f
1 +1 0 +1 0 0 +1
2 -1 -1 0 +1 0 0
3 0 +1 0 0 +1 -1
4 0 0 -1 -1 -1 0

The corresponding graph is

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BPSC AE Paper 5 (Electrical) 25 Mar 2022 Official Paper
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  1. F2 Madhuri Engineering 20.05.2022 D8
  2. F2 Madhuri Engineering 20.05.2022 D9
  3. F2 Madhuri Engineering 20.05.2022 D10
  4. F2 Madhuri Engineering 20.05.2022 D11

Answer (Detailed Solution Below)

Option 2 : F2 Madhuri Engineering 20.05.2022 D9
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Concept:

  • The no. of rows in an incident matrix determines the total no. of nodes present in a graph.
  • The no. of columns in an incident matrix determines the total no. of branches present in a graph.
  • The incoming arrow to a node is taken as -1.
  • The outgoing arrow to a node is taken as +1.

Explanation:

  a b c d e f
1 +1 0 +1 0 0 +1
2 -1 -1 0 +1 0 0
3 0 +1 0 0 +1 -1
4 0 0 -1 -1 -1 0

Following are the results from the above incident matrix:

No. of rows = 4 = Total no. of nodes

No. of columns = 6 = Total no. of branches

Node 1: Three outgoing arrows

Node 2: Two incoming and one outgoing arrow

Node 3: One incoming and two outgoing arrows

Node 4: Three incoming arrows

All the above conditions are fulfilled by option 2.

F2 Madhuri Engineering 20.05.2022 D22

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