Question
Download Solution PDFThe emitter current in a junction with normal bias
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFor a transistor, the base current, the emitter current, and the collector current are related as:
IE = IB + IC
IB = Base current
IC = Collector current
Example:
The current flow for an npn transistor is as shown:
The emitter current is equal to the sum of base current and collector current.
IE = IB + IC
Important Differences between different transistor configuration is as shown:
|
|
Common Base |
Common Emitter |
Common Collector |
|
Input Current |
Ie |
Ib |
Ib |
|
Output Current |
Ic |
Ic |
Ie |
|
Current Gain |
\({α _{dc}} = \frac{{{I_C}}}{{{I_E}}}\) |
\({β _{dc}} = \frac{{{I_C}}}{{{I_B}}}\) |
\(\gamma = \frac{{{I_E}}}{{{I_B}}} \) \({1 + {β _{dc}}}\) |
|
Voltage Gain |
Medium |
Medium |
Less Than 1 |
Last updated on May 30, 2025
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