Question
Download Solution PDFThe electric field intensity at a point due to a uniformly charged infinite plane sheet depends on the:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Gauss law:
- According to the Gauss law, the total flux associated with any closed surface is 1/ε0 times the total charge enclosed by the closed surface.
\(\Rightarrow ϕ=\int \vec{E}.\vec{dA}=\frac{q}{ϵ_{o}}\)
Electric field intensity due to a uniformly charged infinite plane sheet:
- The electric field intensity at a point due to a uniformly charged infinite plane sheet is given as,
\(\Rightarrow E=\frac{σ}{2ϵ_o}\)
Where σ = surface charge density, and ϵo = permittivity
- The electric field intensity due to a uniformly charged infinite plane sheet does not depend on the distance of the point from the plane sheet.
EXPLANATION:
- We know that the electric field intensity at a point due to a uniformly charged infinite plane sheet is given as,
\(\Rightarrow E=\frac{σ}{2ϵ_o}\) ---(1)
Where σ = surface charge density, and ϵo = permittivity
- By equation 1 it is clear that the electric field intensity due to a uniformly charged infinite plane sheet depends on the surface charge density only. Hence, option 1 is correct.
Last updated on May 19, 2025
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