Question
Download Solution PDFThe dimensions of electrical conductivity is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCALCULATION:
1. The resistance may be written as
\(⇒ R =\frac{V}{I} =\frac{W}{I^2t^{}}\)
Where W is the work done and I is the current and t is the time
The dimension of R will be given by
\(⇒ \frac{W}{I^2t^{}}= \frac{ML^{2}T^{-2}}{A^{2}T} = ML^{2}T^{-3}A^{-2}\)
2. The resistivity is given by
\(⇒ \rho = \frac{RA}{l}\)
Where A =Area and l = length
The dimension of resistivity is
\(⇒ \rho = \frac{RA}{l} = \frac{ML^{2}T^{-3}A^{2}\times L^{2}}{L} = ML^{3}T^{-3}A^{-2} \)
3. As we know, the conductivity is the inverse of resistivity taking the inverse of the dimension of resistivity, then the dimension of electrical conductivity is
⇒ σ = M-1L-3T3A2
Last updated on Jun 17, 2025
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