The differential equation of the family of lines y = mx is:

  1. y dx - x dy = 0
  2. y dx + x dy = 0

Answer (Detailed Solution Below)

Option 2 : y dx - x dy = 0
Free
UPSC NDA 01/2025 General Ability Full (GAT) Full Mock Test
150 Qs. 600 Marks 150 Mins

Detailed Solution

Download Solution PDF

Concept:

A differential equation is defined as the equation that contains derivatives of one or more dependent variables with respect to one or more independent variables.

Calculation:

Given that y = mx.
On differentiating both sides, we will get:

.

Substituting  will give us:

⇒ x dy = y dx

y dx - x dy = 0, which is the required differential equation.

Latest NDA Updates

Last updated on Jul 8, 2025

->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.

->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

Hot Links: teen patti star apk teen patti all game teen patti master real cash teen patti master purana