Question
Download Solution PDFIf y = p sin3x + q cos 3x then which of the relation is true for the function
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Some useful formulas are:
\(\rm {d(sinax)\over dx} =a\ cosax\)
\(\rm {d(cosax)\over dx} =-a\ sinax\)
Calculation:
y = p sin3x + q cos 3x
Differentiating the above equation we get,
\(\rm {dy\over dx} =3p\cos3x-3q\sin3x\)
Differentiating further we get,
\(\rm {d^2y\over dx^2} =-9p\sin3x-9q\cos3x\) = -9y
∴ \(\rm {d^2y\over dx^2} +9y=0\)
Last updated on Jun 11, 2025
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