Question
Download Solution PDFకారుకు అప్లై చేయబడ్డ బ్రేకులు చలనానికి వ్యతిరేక దిశలో 10మీ/సె2 త్వరణాన్ని ఉత్పత్తి చేస్తాయి. బ్రేకులు వేసిన తర్వాత కారు ఆగిపోవడానికి 3 సెకన్లు తీసుకుంటే, ఈ సమయంలో అది ప్రయాణించే దూరాన్ని లెక్కించండి.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFమనకివ్వబడింది
a = –10 మీ/సె2; t = 3 సె మరియు v = 0 మీ/సె.
v = u + at
0 = u + (–10 మీ/సె2) × 3సె
u = 30 మీ/సె
s = u t + 1/2 a t2
= 30 × 3 + 1/2 × -10 × 3 × 3
= 90 - 45
= 45 మీ
Last updated on Jun 2, 2025
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