ఇచ్చిన చిత్రంలో, ABC త్రిభుజం వైశాల్యం 80 సెం.మీ2 మరియు BC = 10 సెం.మీ, అప్పుడు చతురస్రం PQRS యొక్క భుజం (సెం.మీ.లో) ఎంత?

F1 Mohd.S 16-05-2020 Shradha D19

  1. 80/17
  2. 80/13
  3. 70/13
  4. 90/13

Answer (Detailed Solution Below)

Option 2 : 80/13
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F1 Mohd.S 16-05-2020 Shradha D20

ABC త్రిభుజం వైశాల్యం = 1/2 × BC × ఎత్తు

⇒ 80 = 1/2 × 10 × ఎత్తు

⇒ ఎత్తు = 16 సెం.మీ

మనకు తెలుసు PQRS చతురస్రం యొక్క భుజం = 

\(\frac{{{\rm{Base}}\; \times \;{\rm{Height}}}}{{\left( {{\rm{Base}}\; + \;{\rm{Height}}} \right)}}\)

⇒ చతురస్రం PQRS యొక్క భుజం =

\(\frac{{10\; \times \;16}}{{10\; + \;16}}\)

⇒ చతురస్రం PQRS యొక్క భుజం =

\(\frac{{160}}{{26}} = \frac{{80}}{{13}}{\rm{\;cm}}\)

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