Question
Download Solution PDFΔ PQRలో, S అనేది QR యొక్క మధ్య బిందువు మరియు PS = SR. ఒకవేళ ∠Q = 48° అయితే, అప్పుడు ∠SPR యొక్క కొలత (డిగ్రీలలో) ఎంత ఉంటుంది?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చినది :
S అనేది మధ్య బిందువు.
మరియు PS = SR
∠Q = 48°
గణన :
నుండి, SR = PS మరియు QS = SR
కాబట్టి, PS = SR = QS
ΔPQS లో,
∠Q = 48°, ∠P = 48°
⇒ ∠Q + ∠P + ∠S = 180°
⇒ ∠S = 180° - 96° = 84°
ఇప్పుడు, ∠QSP + ∠PSR = 180°
⇒ 84° + ∠PSR = 180°
⇒ ∠PSR = 180° - 84° = 96°
ΔPSR లో,
⇒ ∠P + ∠S + ∠R = 180°
⇒ 96° + x + x = 180°
⇒ 2x = 180° - 96° = 84°
⇒ x = 42°
∠SPR = 42°
∴ సరైన సమాధానం 42°.
Last updated on May 9, 2025
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