Question
Download Solution PDF\(\rm KCIO_3\xrightarrow{Moist\ oxalic\ acid}?\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Reaction of Potassium Chlorate (KClO3) with Moist Oxalic Acid
- Potassium chlorate (KClO3) undergoes a redox reaction in the presence of moist oxalic acid (C2H2O4).
- Oxalic acid acts as a reducing agent, while KClO3 acts as an oxidizing agent.
- During the reaction, KClO3 is reduced to chlorine dioxide (ClO2), and oxalic acid is oxidized to carbon dioxide (CO2).
- Potassium ions from KClO3 combine with oxalate ions to form potassium oxalate (K2C2O4).
EXPLANATION:
KClO3 + C2H2O4 → K2C2O4 + ClO2 + CO2
- Given reaction:
- Steps in the reaction:
- Oxalic acid (C2H2O4) is oxidized to carbon dioxide (CO2).
- KClO3 is reduced to chlorine dioxide (ClO2).
- Potassium ions (K+) from KClO3 react with oxalate ions (C2O42−) to form potassium oxalate (K2C2O4).
Therefore, the correct answer is Option 3: K2C2O4 + ClO2 + CO2.
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