In alkaline medium, \(\mathrm{MnO}_{4}^{-}\) oxidises I- to

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  1. IO-
  2. \(\mathrm{IO}_{4}^{-}\)
  3. I2
  4. \(\mathrm{IO}_{3}^{-}\)

Answer (Detailed Solution Below)

Option 4 : \(\mathrm{IO}_{3}^{-}\)
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AIIMS BSc NURSING 2024 Memory-Based Paper
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CONCEPT:

Oxidation in Alkaline Medium

  • In an alkaline medium, the oxidation states of various species can change due to the presence of hydroxide ions (OH-).
  • Permanganate ion (MnO4-) is a strong oxidizing agent, and its ability to oxidize other species varies with the medium (acidic, neutral, or alkaline).

EXPLANATION:

  • In an alkaline medium, MnO4- oxidizes iodide ions (I-) to iodate ions (IO3-).
  • The balanced half-reaction for the oxidation of I- in alkaline medium is:

    MnO4- + I- + OH- → IO3- + MnO2 + H2O

Therefore, in alkaline medium, MnO4- oxidizes I- to IO3-.

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