Question
Download Solution PDFPeak Inverse Voltage for a full wave rectifier (Center-Tap), if E is the peak voltage is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPeak Inverse Voltage is the maximum voltage that appears across a reverse-biased diode:
If E is the maximum voltage of the sinusoidal input signal
Then
For Half Wave rectifier \({\rm{PIV\;}} = {\rm{\;}}{{\rm{E}}_{\rm{}}}\)
For Full Wave rectifier \({\rm{PIV\;}} = {\rm{\;}}2{{\rm{E}}_{\rm{}}}\)
For Bridge Wave rectifier \({\rm{PIV\;}} = {\rm{\;}}{{\rm{E}}_{\rm{}}}\)
|
CIRCUIT |
Number of Diodes |
Average DC Voltage (Vdc) |
RMS Current (Irms) |
Peak Inverse Voltage (PIV) |
|
Half-Wave Rectifier |
1 |
\(\frac{{{V_m}}}{\pi }\) |
\(\frac{{{I_{m\;}}}}{2}\) |
\({V_m}\) |
|
Center-Tap Full Wave Rectifier |
2 |
\(\frac{{2{V_m}}}{\pi }\) |
\(\frac{{{I_m}}}{{\sqrt 2 }}\) |
\(2{V_m}\) |
|
Bridge-Type Full Wave Rectifier |
4 |
\(\frac{{2{V_m}}}{\pi }\) |
\(\frac{{{I_m}}}{{\sqrt 2 }}\) |
\({V_m}\) |
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