6x2 - x - 2 = 0 या द्विघात समीकरणाची मुळे किती आहेत?

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  1. \(\frac{2}{3}, \frac{1}{2}\)
  2. \(-\frac{2}{3}, \frac{1}{2}\)
  3. \(\frac{2}{3}, -\frac{1}{2}\)
  4. \(-\frac{2}{3}, -\frac{1}{2}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{2}{3}, -\frac{1}{2}\)
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दिलेल्याप्रमाणे:

6x2 - x - 2 = 0

गणना :

6x2 - x - 2 = 0

⇒ 6x2 - 4 x + 3x - 2 = 0

2x(3x - 2) + 1(3x - 2)

(2x + 1)(3x - 2) = 0

तर, 2x + 1 = 0 आणि 3x - 2 = 0

x = \(-\frac{1}{2}\) आणि x = \(\frac{2}{3}\)

∴ योग्य उत्तर पर्याय 3 आहे.

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