Question
Download Solution PDFगाडीवर ब्रेक लावले जातात, तेव्हा ते वेगाच्या विरूद्ध 10 मी/से2 त्वरण उत्पन्न करते. ब्रेक लावल्यानंतर गाडी थांबायला 3 सेकंद घेतल्यास, या दरम्यान पार केलेले अंतर मोजा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्या माहितीनुसार
a = –10 मी/से2; t = 3 सेकंद आणि v = 0 मी/से.
v = u + at
0 = u + (–10 मी/से2) × 3 सेंकद
u = 30 मी/से
s = u t + 1/2 a t2
= 30 × 3 + 1/2 × -10 × 3 × 3
= 90 - 45
= 45 मीटर
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