वर्तुळात अंतर्लिखित असलेल्या समभुज त्रिकोणाचे क्षेत्रफळ 4√3 चौ. सेमी आहे तर वर्तुळाचे क्षेत्रफळ किती असेल?

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Territorial Army Paper I : Official Practice Test Paper - 2
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  1. \(\dfrac{16}{3}\pi\)
  2. \(\dfrac{22}{3}\pi\)
  3. \(\dfrac{28}{3}\pi\)
  4. \(\dfrac{32}{3}\pi\)

Answer (Detailed Solution Below)

Option 1 : \(\dfrac{16}{3}\pi\)
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दिलेले आहे

समभुज त्रिकोण हा एका वर्तुळात अंतर्लिखित आहे

समभुज त्रिकोणाचे क्षेत्रफळ = 4√3 चौ. सेमी

वापरलेली संकल्पना 

समभुज त्रिकोणाचे क्षेत्रफळ\(\frac{{√ 3 }}{4}{a^2}\)

गणना

\(\frac{{√ 3 }}{4}{a^2}\) = 4√3 

a2 = 16

a = 4

समभुज त्रिकोणाची परिमिती = \(\frac{a}{{\sqrt 3 }}\)

r = \(\frac{4}{{\sqrt 3 }}\)

वर्तुळाचे क्षेत्रफळ = πr2

πr2 = \(\pi \times \frac{4}{{\sqrt 3 }} \times \frac{4}{{\sqrt 3 }}\)

क्षेत्रफळ\(\dfrac{16}{3}\pi\) चौ. सेमी

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