दिलेल्या आकृतीमध्ये ABCD हा समभुज चौकोन आहे, x चे मूल्य आहे.

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CUET General Test 6th Oct 2022 Official Paper
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  1. 40° 
  2. 50° 
  3. 90 °
  4. 60° 

Answer (Detailed Solution Below)

Option 2 : 50° 
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CUET General Awareness (Ancient Indian History - I)
10 Qs. 50 Marks 12 Mins

Detailed Solution

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दिलेल्याप्रमाणे:

∠CAB = 40 °, ∠BDC = x°

संकल्पना:

समभुज चौकोन ABCD मध्ये, सर्व बाजू समान असतात.

समभुज चौकोनाच्या समीप कोनांची बेरीज 180° आहे

गणना:

∠D = 2 × ∠BDC = 2x [ कर्ण समभुज चौकोनातील कोनांना दुभाजक करतात]

∠A = 2 × ∠CAB = 2 × 40 = 80°

आता,

∠CAB + ∠D = 180°

⇒ 80°+ 2x = 180°

⇒ x = 100/2 = 50°

∴ x चे मूल्य 50° आहे.

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