Match List I with List II

List I List II
In Square of opposition Resultant 
A. If 'Some flowers are pink' is False  I. 'I' is False; 'O' is True
B. If 'No girls are birds' is True II. 'A' is False; 'E' is True
C. If 'Some boys are not tall' is False III. 'I' is True; 'O' is False
D. If 'All chocolates are sweet' is True IV. 'E' is False; 'I' is true

Choose the correct answer from the options given below: 

This question was previously asked in
UGC NET Paper 1: Held on 1st Dec 2021 Shift 2
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  1. A‐II, B ‐ III, C ‐ I, D ‐ IV
  2. A ‐ III, B ‐ IV, C ‐ II, D ‐ I
  3.  A ‐ II, B ‐ I, C ‐ IV, D ‐ III
  4.  A ‐ IV, B ‐ II, C ‐ I, D ‐ III 

Answer (Detailed Solution Below)

Option 3 :  A ‐ II, B ‐ I, C ‐ IV, D ‐ III
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UGC NET Paper 1: Held on 21st August 2024 Shift 1
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Detailed Solution

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The square of opposition is a chart that was introduced within classical (categorical) logic to represent the logical relationships holding between certain propositions in virtue of their form.

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Key Points The four corners of this chart represent the four basic forms of propositions recognized in classical logic:

  • A propositions, or universal affirmatives take the form: All S are P.
  • E propositions, or universal negations take the form: No S are P.
  • propositions, or particular affirmatives take the form: Some S are P.
  • O propositions, or particular negations take the form: Some S are not P.
In the Square of opposition Resultant
A. If 'Some flowers are pink' is False 'A' is False; 'E' is True
B. If 'No girls are birds' is True 'I' is False; 'O' is True
C. If 'Some boys are not tall' is False  'E' is False; 'I' is true
D. If 'All chocolates are sweet' is True 'I' is True; 'O' is False

Therefore the correct match is  A-II, B ‐ I, C ‐ IV, D ‐ III

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