In an orthogonal turning process the chip thickness = 0.32 mm, feed = 0.2 mm/rev. Then the chip reduction coefficient will be

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ESE Mechanical 2014 Official Paper - 2

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Answer 1

Concept:

Chip reduction coefficient is given as,

\(\xi = \frac{t_c}{f}\)

The chip thickness (\(t_c\)) is 0.32 mm, and the feed (\(f\)) is 0.2 mm/rev.

Calculation:

Given:

Chip thickness, \(t_c = 0.32 \text{ mm}\)

Feed, \(f = 0.2 \text{ mm/rev}\)

The chip reduction coefficient is,

\(\xi = \frac{0.32 \text{ mm}}{0.2 \text{ mm/rev}}\)

Perform the division,

\(\xi = \frac{0.32}{0.2} = 1.6\)

The chip reduction coefficient (\(\xi\)) is 1.6.