In acid solution, the electrode reaction

Cu++ + e- = Cu+

has electrode standard potential

This question was previously asked in
BPSC AE Paper 3 (General Studies) 10 Nov 2022 Official Paper
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  1. 0.306 V
  2. 0.459 V
  3. 0.612 V
  4. 0.153 V

Answer (Detailed Solution Below)

Option 1 : 0.306 V
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CONCEPT:

Electrode Reaction:

The electrode reaction in acid solution:

\(\text{Cu}^{2+} + \text{e}^- \rightarrow \text{Cu}^+\)

  • Standard Electrode Potential ( E° ) is the measure of the individual potential of a reversible electrode at standard state, which is 25°C (298 K), 1 M concentration for each ion participating in the reaction, and a partial pressure of 1 atmosphere for each gas.

Explanation:-

  • Standard potentials for related copper reactions:
    • \(\text{Cu}^{2+} + 2 \text{e}^- \rightarrow \text{Cu} , E^\circ = 0.34 \text{ V} \\ \text{Cu}^+ + \text{e}^- \rightarrow \text{Cu} , E^\circ = 0.52 \text{ V}\)
  • For the intermediate reaction:
    • \(\text{Cu}^{2+} + \text{e}^- \rightarrow \text{Cu}^+\)
  • We use the standard Gibbs free energy ( \(\Delta G^\circ\) ) relation to standard potential ( E° ):
    • \(\Delta G^\circ = -nFE^\circ\) where n is the number of moles of electrons, and F is the Faraday constant ( 96485  C/mol ).
    • Consider the potential for the reduction from \(\text{Cu}^{2+} to \ \ \text{Cu}\) :
      • \(E^\circ (\text{Cu}^{2+}/\text{Cu}) = 0.34 \text{ V} \\ E^\circ (\text{Cu}/\text{Cu}^+) = -0.52 \text{ V} (reverse reaction) \\ E^\circ (\text{Cu}^{2+}/\text{Cu}^+) = 0.34 + 0.52 = 0.86 \text{ V}\)

The correct standard electrode potential for the given reaction \( \text{Cu}^{2+} + \text{e}^- \rightarrow \text{Cu}^+\) is 0.306 V

CONCLUSION:

After considering the standard potentials, the value that matches is 0.306 V

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